Let’s proceed the syllogism.
N – is the planet’s rotational spin
cp – is the planet’s average surface specific heat
N*cp is the product of planet’s N and cp
Now, let’s have two identical planets, but with different rotational spin N1 and N2, and with different average surface specific heat cp1 and cp2. Which planet has the highest mean surface temperature Tmean ?
Of course, since every planet has its own unique rotational spin (diurnal cycle) and every planet has its own unique average surface specific heat… we should compare for the two planets N*cp – the product of N and cp.
Consequently, the planet with the highest N*cp product should be the planet with the highest mean surface temperature Tmean.
Earth’s N.earth = 1 rot /day
Moon’s N.moon = 1 /29,5 rot /day
Earth’s cp.earth = 1 cal /gr.oC (watery planet)
Moon’s cp.moon = 0,19 cal /gr.oC (regolith)
(N.earth)*(cp.earth) = 1*1 = 1 rot.cal /day.gr.oC
(N.moon)*(cp.moon) = (1 /29,5)*0,19 = 0,00644 rot.cal /day.gr.oC
Let’s compare the products:
(N.earth)*(cp.earth) / [(N.moon)*(cp.moon)] = 1 /0,00644 = 155,3
What we see here is that the Earth’s N*cp product is 155,3 times higher than the Moon’s N*cp product.
And the satellite measured mean surface temperatures are
Tmean.earth = 287,16 K
Tmean.moon = 220 K
It is obvious that Earth’s higher rotational spin and Earth’s higher surface specific heat make Earth a warmer than Moon planet.