The Planet Mean Surface Temperature Equation: Tmean=[Φ(1-a)S(β*N*cp)¹∕ ⁴ /4σ]¹∕ ⁴

The Earth seen from Apollo 17

Europa moon with margins

Earth / Europa (Jupiter's moon) satellite measured mean surface temperatures 288 K and 102 K comparison

 

All the data below are satellites measurements. All the data below are observations.

Planet….Earth….Europa

Tsat.mean 288 K….102 K

R…...........1 AU…5,2044 AU

1/R²………1…….0,0369

N………....1……0,28159 rot./day

a…………..0,306……0,63

(1-a)………0,694……0,37

coeff...0,9127...0,3158

 

Comparison coefficient calculation

[ (1-a) (1/R²) (N)¹∕ ⁴ ]¹∕ ⁴

 

Earth:

Tsat.mean = 288 K

[ (1-a)*(1/R²)*(N)¹∕ ⁴ ]¹∕ ⁴ =

= ( 0,694 * 1 * 1 )¹∕ ⁴ = 0,9127

 

Europa:

Tsat.mean = 102 K

[ (1-a)*(1/R²)*(N)¹∕ ⁴ ]¹∕ ⁴ =

= [ 0,37*0,0369*(1/3,5512)¹∕ ⁴ ] ¹∕ ⁴ = 0,3158

 

Let's compare

Earth coeff. /Europa coeff. =

= 0.9127 /0,3158 = 2,8902

And

Tmean.earth /Tmean.europa =

= 288 K /102 K = 2,8235

 

Conclusion:

Everything is all right. Everything is based on observations. 

Notice:

We could successfully compare Earth /Europa ( 288 K /102 K ) satellite measured mean surface temperatures because both Earth and Europa have two identical major features.

Φearth = 0,47 because Earth has a smooth surface and Φeuropa = 0,47 because Europa also has a smooth surface.

cp.earth = 1 cal/gr*°C, it is because Earth has a vast ocean. Generally speaking almost the whole Earth’s surface is wet. We can call Earth a Planet Ocean.

Europa is an ice-crust planet without atmosphere, Europa’s surface consists of water ice crust, cp.europa = 1cal/gr*°C.

And

It is a confirmation that the planet axial spin (rotations per day) "N" should be considered in the (Tmean) planet mean surface temperature equation in the fourth root:

Tmean.planet = [ Φ (1-a) So (1/R²) (β*N*cp)¹∕ ⁴ /4σ ]¹∕ ⁴.

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