Mercury / Mars satellite measured mean surface temperatures 340 K and 210 K comparison

These ( Tmean, R, N, and albedo ) planets' parameters are all satellites measured. These planets' parameters are all observations.

Planet….Mercury….Moon….Mars

Tsat.mean.340 K….220 K…210 K

R…......0,387 AU..1 AU..1,525 AU

1/R²…..6.6769….....1….…0,430

N…1 /175,938..1 /29,531..0,9747

a......0,068......0,11......0,250

1-a….0,932……0,89…….0,75

coeff...1,1371.............0,7524

Comparison coefficient calculation

[ (1-a) (1/R²) (N)¹∕ ⁴ ]¹∕ ⁴

Mercury:

Tsat.mean = 340 K

[ (1-a)*(1/R²)*(N)¹∕ ⁴ ]¹∕ ⁴ =

= [ 0,932*6,6769*(1/175,938)¹∕ ⁴ ] ¹∕ ⁴ = 1,1433

Mars:

Tsat.mean = 210 K

[ (1-a)*(1/R²)*(N)¹∕ ⁴ ]¹∕ ⁴ =

= [ 0,75*0,430*(0,9747)¹∕ ⁴ ] ¹∕ ⁴ = 0,7524

Let's compare

Mercury coeff. / Mars coeff. =

= 1,1433 /0,7524 = 1,5195

And

Tmean.mercury /Tmean.mars =

= 340 K /210 K = 1,6190

The Mercury's comparison coefficient (1,1433) is calculated for Mercury's Semi-major axis which is 0,387 AU. But half of the time, Mercury comes closer to the sun at its Perihelion of 0,307 AU. The fact Mercury's orbit has high eccentricity e = 0,205 partly explains the difference between the calculated (1,5195) and the measured (1,6190).

Conclusion:

Everything is all right.

It is a demonstration of the Planet Surface Rotational Warming Phenomenon!

And

It is the confirmation that the planet axial spin (rotations per day) "N" should be considered in the (Tmean) planet surface mean temperature equation in the sixteenth root:

Tmean.planet = [ Φ (1-a) So (1/R²) (β*N*cp)¹∕ ⁴ /4σ ]¹∕ ⁴.