Mercury / Mars satellite measured mean surface temperatures 340 K and 210 K comparison
Mercury / Mars satellite measured mean surface temperatures 340 K and 210 K comparison
These ( Tmean, R, N, and albedo ) planets' parameters are all satellites measured. These planets' parameters are all observations.
Planet….Mercury….Moon….Mars
Tsat.mean.340 K….220 K…210 K
R…......0,387 AU..1 AU..1,525 AU
1/R²…..6.6769….....1….…0,430
N…1 /175,938..1 /29,531..0,9747
a......0,068......0,11......0,250
1-a….0,932……0,89…….0,75
coeff...1,1371.............0,7524
Comparison coefficient calculation
[ (1-a) (1/R²) (N)¹∕ ⁴ ]¹∕ ⁴
Mercury:
Tsat.mean = 340 K
[ (1-a)*(1/R²)*(N)¹∕ ⁴ ]¹∕ ⁴ =
= [ 0,932*6,6769*(1/175,938)¹∕ ⁴ ] ¹∕ ⁴ = 1,1433
Mars:
Tsat.mean = 210 K
[ (1-a)*(1/R²)*(N)¹∕ ⁴ ]¹∕ ⁴ =
= [ 0,75*0,430*(0,9747)¹∕ ⁴ ] ¹∕ ⁴ = 0,7524
Let's compare
Mercury coeff. / Mars coeff. =
= 1,1433 /0,7524 = 1,5195
And
Tmean.mercury /Tmean.mars =
= 340 K /210 K = 1,6190
The Mercury's comparison coefficient (1,1433) is calculated for Mercury's Semi-major axis which is 0,387 AU. But half of the time, Mercury comes closer to the sun at its Perihelion of 0,307 AU. The fact Mercury's orbit has high eccentricity e = 0,205 partly explains the difference between the calculated (1,5195) and the measured (1,6190).
Conclusion:
Everything is based on observations in
the comparison coefficient
[ (1-a) (1/R²) (N)¹∕ ⁴ ]¹∕ ⁴
And
It is the confirmation that the planet axial spin (rotations per day) "N" should be considered in the (Tmean) planet surface mean temperature equation in the fourth root:
Tmean.planet = [ Φ (1-a) So (1/R²) (β*N*cp)¹∕ ⁴ /4σ ]¹∕ ⁴.
.